A Temperature Change From 35ã´â‚¬ââ±c To 55ã´â‚¬ââ±c Corresponds To What Incremental Change In ô€ââ±f?
Part A For the reaction 2C H iv (g)⇌ C 2 H ii (g)+3 H 2 (chiliad) K c = 0.155 at 1507 ∘ C . What is K p for the reaction at this temperature? Express your answer numerically. Part B For the reaction Northward ii (g)+3 H 2 (g)⇌2N H 3 (thou) K p = 4.55×10−3 at 269 ∘ C . What is Yard c for the reaction at this temperature? Enter your respond numerically.
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Related Question
Calculate $K_{\mathrm{c}}$ for each reaction: a. $\mathrm{I}_{2}(g) \rightleftharpoons ii \mathrm{I}(k) \quad K_{\mathrm{p}}=6.26 \times x^{-22}$ (at $\left.298 \mathrm{~Grand}\right)$ b. $\mathrm{CH}_{four}(g)+\mathrm{H}_{two} \mathrm{O}(chiliad) \rightleftharpoons \mathrm{CO}(chiliad)+iii \mathrm{H}_{2}(g)$ $K_{\mathrm{p}}=7.seven \times 10^{24}($ at $298 \mathrm{~K})$ c. $\mathrm{I}_{2}(k)+\mathrm{Cl}_{2}(thou) \rightleftharpoons 2 \mathrm{ICl}(g) \quad K_{\mathrm{p}}=81.9($ at $298 \mathrm{~Grand})$
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Video Transcript
for united states of america to respond this question, we have to wait at the human relationship between K. P and Casey and this is equal to K. C. Multiplied past RT raised the power of delta and well delta. And it's only a modify in the strict geometric coefficients. The key metric coefficient in that reaction. So all nosotros have to do here is to for example, if nosotros are calculating for Casey, Casey is going to be equal to Thousand P divided by party multiplied past talk to him. So for example, for the first reaction that we've been given first reaction nosotros've got itunes for me 2. And if we are to look at this, nosotros're going to tell that delta North is equal to two. My nurse i. This is equal to one. Call back delta. And it'south just the change in this documentary coefficients. That is the country geometric coefficients of the products miners that of the reactions y'all've got to stop here. This is just one. Then delta N is equal to minus one which is one. So if we are to couple casing, our Casey is going to exist equal to our K. P. Which is 6.26 Times ten to the power negative 2, 2 divided by Our which is zero 08- 06. Multiplied by our temperature which is true 98. And the season Calvin raised to the power of one. Retrieve 0.08-0 half dozen is given in letters temper. Okay, more killing. So our temperature has to be in and kill. And so cooperating KCRKC is going to be equal to ii.v Times 10 to the power negative. True. Moving on to the side by side reaction. We've got marsh gas reacting with water Form Cup on ane outside and hydrogen. This is three. And then Our daughter and is going to be equal to we take 3 plus i minus if one plus ane. So this is going to be delta and is equal to mm. And so our Casey PC is going to be equal to 7.7 trans 10 to the power 22. This is 24 divided past 0.08- 06. Multiplied by the temperature Which is to 98. And think we take to raise these to the poor. True. So our Casey Our Casey is going to be equal to 123 Times ten to the power 22. And then moving on to the final one where nosotros have I to bless the Fifty ii forming to I. C. 50. And then if we look at our delta and this is quite a tu minus one minus ane. And then this is going to be equal job zero. So our Casey is going to exist equal to viii. Divided by 0.0 8-0 6 Terms to 98. All of these raised to the ability of zero. So this is going to be eight. divided by one. And then our Casey is going to be equality 81 betoken right
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